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2014-06-27T17:52:30+08:00

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7x²+3x=0, make a value 1 so dive all by 7
x²+3/7x=0, 
x²+3/7x+3/196=3/196, complete the square of x
(x+3/14)²=3/196,express the term on the right as square of binomial
x+3/14=√3/√196, extract the square roots
x+3/14=+or-√3/14, only 196 ha square root so 3 remain the same
x=3/14+or-√3/14, apply ape
first solution is
x=3/14+√3/14
the second is 
x=3/14-√3/14
the equation is unfactorable but this are the solutions 




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2014-06-27T17:58:33+08:00

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7x² + 3x = 0



x (7x + 3) = 0



x=0  ;  7x+3=0



x=0  ;  x= -3/7
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