Answers

2014-06-28T13:59:01+08:00
 x^{2} =15
 \sqrt{x^2}= \sqrt{15}
x= +or-\sqrt{15}

 x^{2} =20
 \sqrt{x^2} =  \sqrt{20}
x= + or - \sqrt{20}

 x^{2} =48
 \sqrt{x^2}= \sqrt{48}
x= +or- \sqrt{48}

P.S. :The given equations can't be factored so I used "Extracting the Roots" method. ^_^ \/

1 5 1
2014-06-28T16:49:35+08:00
1.x= √15
2. x= 2√5
3.x=2√12
0