Find three consecutive odd numbers whose sum is 69

2
by Raventserof

2015-09-14T21:22:34+08:00

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(x-2) + x + (x+2) = 69
3x - 69 -> x - 23

the numbers are 21, 23 and 25.
Incorrect. The numbers are 25, 27, and 29 :-)
sorry, you are right. I apologize. The inequality equation confused me. That part 3x-69 is greater or equal than x-23. With that, x is greater than or equal to 23. If we are looking for odd number, when x is greater or equal than 23, then 24 is included which is an even number, and 23 is the minimum or lowest among the three odds. Unless, there's an error in typing. While the answers is right, where your solution solved for the middle of the 3 odd integers, the solution may be simpler. :-)
:)
You could have presented the solution in a simpler way :-) The problem stated the sum, so you just add up and solve for x using property of equality. :-)
• Brainly User
2015-09-15T02:16:20+08:00

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Let the first odd number be x
second odd number be x+2
third odd number be x+4
the sum of the three consecutive odd integers = 69

Equation:

(x) + (x+2) + (x+4) = 69
3x + 6 = 69

3x = 69 - 6
3x = 63

3x/3 = 63/3
x = 21

The three consecutive odd integers are:
x = 21
x+2 = 23
x + 4 = 25

To check:
21 + 23 + 25 = 69
69 = 69