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let 'x' be the age of the father when his age was twice as his son

and 'y' be the age of his son at that time

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so if the father's age was twice as his son then

x = 2y -----equation 1

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Given the ages of the two at present as

father = 52

son = 27

we find the difference between their age

52 - 27 = 25

25 I constant as per difference of their age no matter what year it is so we say that during the time when father's age was twice as the son, the difference of their ages is the same which is 25. so we'll have:

x - y = 25 ----equation 2

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Substitute equation 1 to equation 2 we'll have

x - y = 25 where x=2y

2y - y = 25

__y = 25__

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substitute y=25 to equation 1

x = 2y

x = 2(25)

__x = 50__

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Therefore it happened when the father was 50 years old and the son was 25yrs old or that would be 2 years ago.

27 - 2 = 25

25 x 2 = 50

So therefore the answer is :

The father was twice as old as his son when he was 50, and when his son was 25.