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From 2006 through 2013, the average weekly income of an employee in a certain company is estimated by the quadratic expression 0.18n² + 6.48n + 3240 where

n is the number of year after 2006. In what year did the average weekly income of an employee become 368?
uhmmm what year is that?
Ok wait, my solution is wrong... I'll rewrite it, give me a moment
Whatever I do, it never gives a exact answer... Its always an imaginary value... Is that okay?
ok ill try to explain to my teacher


 \frac{18n^2+6.48n}{18}=  \frac{-3240}{18}
 \sqrt{(n+0.18)^2}= \sqrt{-179.9676}
n+0.18= \sqrt{-179.9676}*(-1)
n+0.18= \sqrt{1799676 }i
n=+or-  \sqrt{179.9676}i-0.18

That was confusing with all the decimals...Sorry for the late answer... :o
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