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2015-09-25T18:05:18+08:00

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When multiplying numbers with the same base, we just add the exponents, and that will be the exponent of the product.

k^{2/5}*k^{6/7}=k^{2/5+6/7}=k^{44/35}= \sqrt[35]{k^{44}}
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  • Brainly User
2015-09-26T03:15:45+08:00
1) Change the fractional exponents to similar fractions.  LCD of denominators 5 and 7 is 35.

2) Re-write as:
  
(k ^{ \frac{14}{35} } ) (k ^{ \frac{30}{35} } )

3) Multiply (add the exponents):
   
 (k ^{ \frac{14}{35} } ) (k ^{ \frac{30}{35} } ) = k ^{ \frac{44}{35} }

4) As radical expression, the denominator is the nth root, the numerator is the exponent of the radicand k.

k ^{ \frac{44}{35} } =   \sqrt[35]{k ^{44} }
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