Chemical analysis of one of the constituents of gasoline showed that it consists of 92.29% carbon and 7.71% hydrogen by mass. If the molecular mass of the compound is 78 g/mol, determine its molecular formula. (C6H6)

Do you use carbon=12amu and hydrogen =1amu ?



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The compound is CnHm 

(\frac{78g}{mol}) (0.9229) = \frac{71.9862g}{mol}  (mass of Carbon)

(\frac{71.9862g}{mol})( \frac{1mol}{12g}) = 5.998 = 6  = n

(\frac{78g}{mol}) (0.0771) = \frac{6.0138g}{mol}  (mass of Hydrogen)

(\frac{6.0138g}{mol})( \frac{1mol}{1g}) = 6.0138 = 6  = m

Its Molecular Formula is C₆H₆