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(4x²y³/8z³)³  (-xy³/z)

=  (x²y³/2z³)³  (-xy³/z)

( \frac{x ^{6}y ^{3}  }{8z ^{9} } )( \frac{-xy ^{3} }{yz} )

 \frac{-x ^{7}y ^{6}  }{8z ^{10} }

Please remove the variable "y" in the denominator of -xy^3 in the fourth line. My mistake in typing. But the final answer is correct.