# Four-fifths of the pupils who took the exam passed. eighteen pupils failed the exam. how many pupils passed?

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by dudu

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by dudu

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Let the total number of pupils be x.

If 5/5 is the total (whole) and 4/5 passed the exams, then 1/5 failed:

5/5 - 4/5 = 1/5

1/5 of the total pupils who failed the exams is 18:

(1/5)(x) = 18

(1/5)(x)(5/1) = 18 (5/1) (multiply both sides of equation by 5/1, the

reciprocal of the coefficient of x)

x = (18)(5)

x =*90, the total number of pupils who took the exams.*

(4/5)(90) = number of pupils who passed

360/5 =__72, the number of pupils who passed the exams__

If 5/5 is the total (whole) and 4/5 passed the exams, then 1/5 failed:

5/5 - 4/5 = 1/5

1/5 of the total pupils who failed the exams is 18:

(1/5)(x) = 18

(1/5)(x)(5/1) = 18 (5/1) (multiply both sides of equation by 5/1, the

reciprocal of the coefficient of x)

x = (18)(5)

x =

(4/5)(90) = number of pupils who passed

360/5 =

1/5=18

2/5=36

3/5=54

4/5=72

So 72 pupils passed.