Answers

2014-07-01T00:46:27+08:00
Chemical engeniring califonia intetute of co2 emessions from fossil fuel cumsomption and they are now excess of 380 reagants for fuel cosimption
0
2014-07-01T01:10:46+08:00

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
1) You need the balanced equation of the reaction.
2) Compute for molar mass of each reagent.
3) Kunin mo yung equivalent moles nila using the given amounts.
4) Multiply each of their moles to the ratio of mole of product (choose any) over mole of reagent.
5) Compare the resulting moles. Kung ano yung may mas mababang result, yun ang limiting reagent.

For example,   4NH₃ + 5O₂ ––> 4NO + 6H₂O         (step 1: balanced na yan)
Given: 2.5g NH₃   and   2.85g O₂

Step 2:      (use periodic table, kung di mo kabisado mass nila)
1 mole NH₃ =  17.03 g
1 mole 
 O₂ = 32.0 g 

Step 3 and 4:     (i chose NO for the ratio)

2.5g NH_{3}  (\frac{1mol}{17.03g}) ( \frac{4molNO}{4molNH_{3}}) = 0.147 mol NO

2.85g O_{2}  (\frac{1mol}{32g}) ( \frac{4molNO}{5molO_{2}}) = 0.071 mol NO

Step 5:
0.147 mol NO > 0.071 mol NO

Therefore, O₂ ang limiting reagent and NH₃ ang excess.
0