__Representation:__

*x = length*

*x- 4 = width ( four inches less than the length)*

*12 square inches = Area*

*Use the formula Area = L × W to find the dimensions.*

__Equation:__

*L × W = Area*

*(x) (x-4) = 12*

__Solution:__

*x² - 4x = 12*

*Transform to quadratic equation, ax² + bx + c = 0*

*x² - 4x - 12 = 0*

*Solve by factoring:*

*(x - 6) (x + 2) = 0*

*x - 6 = 0 x + 2 = 0*

*x = 6 ** **x = -2*

*Choose the positive root, x = 6*

__Answer:__

*Length = x ⇒ x = **6 inches*

*Width = x - 4 ⇒ 6 - 4 = **2 inches*

__The dimensions are 6 inches for length and 2 inches for width.__

*To check:*

*(6 inches) (2 inches) = 12 square inches*

*12 square inches = 12 square inches.*

(On a lighter note: Who wants to be in a study area with dimensions of 2 inches and 6 inches? An adult shoe size is at average 7 to 8 inches. Not even a left or right shoe would fit in. This problem is not a real-life application. Or maybe, it's just me :-) )