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The graph is only found in the left side of the y-axis. Particularly, it is on quadrants 2 and 3.
Correct:-) Further, the graph excludes -4 (shown by broken vertical line passing trough coordinates (4,0) and parallel to y-axis).
Sorry, coordinates (-4,0) NOT (4,0).
I think its a downward of a parabola.
There's no previous equation that proves your answer. That is, we don't know if the equation is more than first degree :-) Also in parabola graph, the value of x (roots) in a given second or more degree equation determines the x-intercepts, not the slope or vertex/vertices that show the curve/s and the minimum (opens upward) or maximum (opens downward), depending on the sign of the coefficient of the leading term :-)