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  • Brainly User
2015-11-11T13:13:30+08:00
Vertices (3, 8) and (15, -4) are opposite vertices connect by a segment to form a diagonal.  The diagonals of a square are congruent.

Distance Formula:
= \sqrt{(x _{2}-x_{1}) ^{2}+ (y_{2}-y_{1} )^{2}   }

x _{1}= 3
x _{2} =15
y _{1} =8
y_{2} =-4

D =  \sqrt{(15-3) ^{2}+(-4-8) ^{2}  }

D =  \sqrt{(12) ^{2}+(12) ^{2}  }

D =  \sqrt{144+144}

D =  \sqrt{288}

D =  \sqrt{(16)(18)}

D = 4 \sqrt{(9)(2)}

D = (4)(3) \sqrt{2}

D = 12 \sqrt{2}    The length of each diagonal of the square

2 5 2