How to solve?? hahati hatiin po sya para mag ka triangle. tapos isosolve using the area of triangle :)

1
Can you give the coordinates of those points? Meron kasing mga hindi sakto, so mahirap hulaan kung saan sila nakatapat.
sige po. :)
A= -3,3
B=-3,-2
C= -2,-4
D= -4,4
E=-3,5
F= 5,3
G=4,4
H=-2, 4
I=-1,6
J=-1,4
K=1,4
L= 1,6
M= -1,3
N=-2,2
O=-1,2
P=2,2
Q=3,3
R=2,4
S=-1,-1
T=3,-1
U=2,-3
V=-2,-1
ate yan po :))) thankiiie!
Ate yun pong U = -2,3

Answers

2014-07-05T20:24:21+08:00

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A=| \frac{-3(3-(-4))-3(-4-(-2))-2(-2-3)}{2}| = 2.5

B=| \frac{4(3-(-4))-3(-4-(-4))-2(-4-3)}{2}|=21

C=| \frac{4(3-4)-3(4-(-4))-2(-4-3)}{2}|=7

D=| \frac{4(4-4)+4(4-(-4))-2(-4-4)}{2}|=24

E=| \frac{4(4-3)+4(3-(-4))+5(-4-4)}{2}|=4

F=| \frac{4(-3-3)+5(3-(-4))+5(-4(-3))}{2}|=3

G = | \frac{-1(6-4)-1(4-4)+1(4-6)}{2}|=2

H=| \frac{1(6-4)-1(4-6)+1(6-6)}{2}|=2

A+B+C+...+H = \boxed{65.5}square units


Area of "eyes and mouth":
\bold1=| \frac{-1(2-2)-2(2-3)-1(3-2)}{2}|=0.5

\bold2=| \frac{3(2-2)+4(2-3)+2(3-2)}{2}|=1

\bold3=| \frac{-1(2-(-2))+3(-2-(-1))-1(-1-(-2))}{2}|=2

\bold4=| \frac{-1(-2-(-1))+3(-1-(-1))+(-1-(-2))}{2}|=2

\bold1+\bold2+\bold3+\bold4=5.5square units


IF we subtract the "holes" from the "head":

65.5 - 5.5 = 60 square units
0
ate pano pong baliktad?
For example, point R. Dapat (4,2) and not (2,4)
ate edi hindi pa po nasosolve yung D, E, R, V, U??
Hindi, okay na lahat. Baliktad lang yung coordinates na nabigay mo, kaya baliktad yung nasulat ko. Pero sa solution, okay na.
Yung sa solution na Letters and Numbers nga pala, yun yung mga triangles na nakuha nung hinati yung figure. Naka-attach yon tignan mo na lang