Answers

2015-11-27T20:47:20+08:00
 x_{1}  =4   
 x_{2} = -6
 y_{1} = -3
 y_{2} = -5

d =  \sqrt{(x_{2}- x_{1})^{2} + (y_{2} - y_{1})^{2}    }
d =  \sqrt{(4-(-6))^{2} + (-3- (-5)) ^{2}  }
d =  \sqrt{(-10)^{2}+ (-2) ^{2}  }
d =  \sqrt{100+4}
d =  \sqrt{104}
d =  \sqrt{4 · 26}
d = 2 \sqrt{26}
1 5 1
thank you very much :)
Incorrect.  The answer is the distance of the diameter NOT the POINT of the center.
Why use distance when the given are endpoints of the diameter?  It's better to use Midpoint formula :-)
I mean the answer given ,2 square root of 26,  is the length of the diameter, not the point of the center :-)
sorry :(
2015-11-28T19:03:11+08:00

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I don't see the use of using the distance formula so I'm going to use the midpoint formula

The midpoint formula is:
( \frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )

So we plug in the values with (4,-3) being x₁ and y
₁ and (-6,-5) being x₂ and y₂.
( \frac{4-6}{2},\frac{-3-5}{2} ) \\\\ ( \frac{-2}{2},\frac{-8}{2} )\\\\(-1,-4)

The coordinates of the center of the diameter of the circle with the given points is (-1,-4)

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