# The area of a rectangular garden is 48 square feet. How much fencing will be needed to enclose it if its length is 2 feet longer than its width?

2
by Stepanyang

2015-12-05T09:14:10+08:00
The answer is 28.

divide 48 with 2 one-digit numbers. in which the other one is greater than 2 then try and multiply them to get the the answer 48.

EX:
1x3 ; 2x4 ; 3x5 an so on..

when you get the answer 48 it would be 6x8. what you do with this is get the perimeter. the equation for getting a perimeter is 2l+2w. 6 is the widht and 8 is the lentgh

P= 2l + 2w
= 8+8+6+6
= 28
• Brainly User
2015-12-05T10:44:58+08:00
Width: x
Lenght:  x+ 2
Area: 48 ft²

Area = (Width) (Length)
48 = (x)(x+2)
48 = x² + 2x

Quadratic Equation, ax² bx + c = 0
x² + 2x - 48 = 0
Factor:
(x + 8) (x - 6) = 0

x + 8 = 0                 x - 6 = 0
x = -8                      x = 6

Choose the positive root, x = 6

Dimensions:
Width, x = 6 ft.
Length, x + 2 = 6 + 2 = 8 ft.

Fencing needed (Perimeter of the rectangular garden):
Perimeter = 2 (Width) + 2 (Length)
P = 2 (6 ft) + 2 (8 ft)
P = 12 ft. + 16 ft.
P = 28 ft.