# A wire whose length is at most 62 cm is bent to form a rectangle. If the length of rectangle is 7 cm longer than the width, what is tje maximum area of rectangle?

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by maeyadoo

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by maeyadoo

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x is one side of the rectangle

x+7 another side

x+x+7=31

2x+7=31

2x=31-7

2x=24

x=12

12+7=19

12 and 19 are the sides of the rectangle

12x19=228cm^2

Lenght: x + 7

Perimeter of the rectangle: 62 cm

Perimeter = 2 (Width) + 2 (Length)

62 = 2 (x) + 2 (x+7)

62 = 2x + 2x + 14

62 - 14 = 4x

48 = 4x

4x/4 = 48/4

x = 12

Substitute 12 for x in dimensions:

Length × Width = Area

(19 cm) (12 cm) =