# Six rectangles each with a common base width of 2 have lengths of 1,4,9,16,25, and 36. What is the sum of the areas of the six rectangles?

2
by chubzmenor

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by chubzmenor

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Common Width of overlapping 6 rectangles: 2 units

Equation:

Sum of the areas = 2 units [ (1 + 4 + 9 + 16 + 25 + 36) units]

= 2 units ( 91 units)

=

A = width × length

A = 2 ( 1 + 4 + 9 + 16 + 25 + 36)

A = 2 (91)

A = 182 units²