# Find the distance in inches between two vertices of a cube that are farthest from each other if an edge measure 10 inches

1
by Kayyyy

• Brainly User
2015-12-31T00:47:18+08:00
The cube has 6 lateral square faces.  The corners are all right angles.  Therefore, use Pythagorean Theorem to solve for hypotenuse/ diagonals/distance between the vertices farthest from each other.

Step 1:  Find the hypotenuse/diagonal of the square (lateral face) given the edge which measures 10 inches.

Diagonal =

Diagonal =

Diagonal =

Diagonal =   =

Diagonal =   inches

Step 2:  Find the distance between the vertices farthest from each other,
Edge = 10 inches
Diagonal of the lateral face/square =   inches

Distance =

Distance =

Distance =

Distance =

Distance =

Distance =

Distance =   inches

Distance ≈ (10) (1.732) inches

Distance ≈ 17. 32 inches

ANSWER:  The distance between the vertices farthest from each other in a cube is inches or approx. 17.32 inches.

Please click image below for my illustration with solution.