Log in to add a comment

Log in to add a comment

y = 3x + 15

A. To solve for y-intercept, substitute 0 for x:

y = 3x 15

y = 3 (0) + 15

B. To solve for x-intercept, substitute 0 for y:

y = 3x + 15

0 = 3x + 15

3x = -15

3x/3 = -15/3

f(x) = 3x + 15

y = 3x +15

y-intercept is simply the value of y when x is zero. Also b in the equation so 15.

x-intercept is the value of x when y is zero.

y = 3x + 15

0 = 3x + 15

-3x = 15

-3x/-3 = 15/-3

x = -5