Answers

2016-01-07T20:23:16+08:00
First, we need to find their volumes.
V = πr²h
V = (3.14)(10 cm)²(8 cm)
V = (3.14)(100 cm²)(8 cm)
V = 2512 cm³ - First milk

Using the same formula...
V = πr²h
V = (3.14)(8 cm)²(10 cm)
V = (3.14)(64 cm²)(10 cm)
V = 2009.6 cm³ - Second milk

Then subtract.
2512 cm³ - 2009.6 cm³ = 502.4 cm³

Therefore, the first milk is can hold 502.4 cm³ more milk than the smaller one.

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thank you very much
My pleasure! ☺♥