# The perimeter of a Rectangle is 64cm, if the length is 4cm more than the width, what is its area?

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Perimeter of rectangle = 2(L) × 2(W)

Solve for x using formula of perimeter:

64 = 2 (x) + 2(x + 4)

64 =2x + 2x + 8

64 = 4x + 8

4x = 64 - 8

4x = 56

4x/4 = 56/4

Dimension:

Solve for Area:

Area = L × W

Area = (18 cm) (14 cm)

ANSWER: The area of rectangle is 252 cm

let x = be the width

x + 4 = be the length

2(2x + 4) = 64

4x = 64 - 8

x =

x + 4 = 14 + 4 =

Area = lw

Area = (14 cm)(18 cm)