# Describe analytically (in terms of equation) The set of points parallel to the x-axis and 5 units away from the point (2,2) (TWO ANSWERS)

1
by agaringarao

• Brainly User
2016-01-13T03:37:07+08:00
The horizontal graph parallel to the x-axis is described by equation:
y = b,  where b is the y-intercept at (0,y), and slope (m) = 0.

1)  The equation 5 units above the point (2,2):
To find the y-intercept given the points, when y=2:
y- intercept  (b) = 2 + 5
y - intercept  (b) = 7

Since the equation for horizontal graph is y = b, therefore the equation 5 units above point (2,2) is:

y = 7

2.)  5 units below the point (2,2):
To find the y-intercept given the points, when y=2:
y-intercept (b) =  2 - 5
y - intercept (b) = -3

Since the equation for the horizontal graph is y = b, therefore, the equation 5 units below point (2,2) is:

y = -3

1)  y = 7
m (slope) = 0
Domain = {x / x is an element of real numbers}
Interval notation:  (⁻∞ , ⁺∞)
Range = {y / y = 7}
=  {7}

2) y = -3
m (slope) = 0
Domain = {x / x is an element of real numbers}
Interval notation: (⁻∞,  ⁺∞)
Range = {y / y= -3}
= {3}

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