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## Answers

2x-3y = 5 <----- subract 2x to both sides

-3y = -2x + 5; divide both sides by -3

**y = (-2/3)x - 5/3**<--- this is the first equation

mx + 3y = 7 <---- subtract mx to both sides

3y = -mx + 3 <----- divide both sides by 3

**y = (-m/3)x + 1**<---- this is the second equation

Now determine the slope of equations 1 and 2.

[the slope is anything that is multiplied to x]

Equation 1: -2/3 <---slope1

Equation 2: -m/3 <----slope2

Now if two line are perpendicular then the slopes of the two equations are negative reciprocals.

Example, if the slope of line1 is 3/5 then the slope of line2 that will make it parallel to line1 is -5/3 <---- notice that you flip the top and bottom numbers and multiplies it to negative 1

Second step get the negative reciprocal of one the slopes and equate it to the slope of the other: -RECIPROCAL slope 1 = slope2

the negative reciprocal of -2/3 is 3/2

then equate it to -m/3

3/2 = -m/3 <---- multiply both sides by 3

9/2 = -m <------ multiply by -1

-9/2 = m <----- flip the equation

__<---- this is the value of m__

**m = -9/2**