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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

First step: express the equation into the form y = (slope)x + b; y is alone on one side

2x-3y = 5 <----- subract 2x to both sides -3y = -2x + 5; divide both sides by -3 y = (-2/3)x - 5/3 <--- this is the first equation

mx + 3y = 7 <---- subtract mx to both sides 3y = -mx + 3 <----- divide both sides by 3 y = (-m/3)x + 1 <---- this is the second equation Now determine the slope of equations 1 and 2. [the slope is anything that is multiplied to x] Equation 1: -2/3 <---slope1 Equation 2: -m/3 <----slope2 Now if two line are perpendicular then the slopes of the two equations are negative reciprocals. Example, if the slope of line1 is 3/5 then the slope of line2 that will make it parallel to line1 is -5/3 <---- notice that you flip the top and bottom numbers and multiplies it to negative 1

Second step get the negative reciprocal of one the slopes and equate it to the slope of the other: -RECIPROCAL slope 1 = slope2 the negative reciprocal of -2/3 is 3/2 then equate it to -m/3 3/2 = -m/3 <---- multiply both sides by 3 9/2 = -m <------ multiply by -1 -9/2 = m <----- flip the equation m = -9/2 <---- this is the value of m