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2016-01-16T11:31:37+08:00

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You can simplify it. Or just this one...
1. Cube the first term.
2. Three times the square of the first term and the second term.
3. Three times the first terms and the square of the second term
4. Cube of the second term.


For example:
(a+b)³ = a^3+3a^2b+3ab^2+b^3
(a-b)³ = a^3-3a^2b+3ab^2-b^3
(4b+3)³ = 64b^3+(3)(16b^2)(3)+(3)(4b)(9)+9\\64b^3+144b^2+108b+9
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LOL I haven't noticed your question... well, just, that's how it is lol.. just uhm ugh >.< nvm..
yikes, just noticed.. it must be Three times the product of the square of the first term and the second term.          3. Three times the product of the first terms and the square of the second term. sorry. I haven't noticed that lol.
  • Brainly User
2016-01-17T16:49:49+08:00
Cube of binomial pattern, where a = first term  and b = second/last term:

         (a + b)³ = (a + b) (a + b) (a + b)
                      = a³ + 3a²b + 3ab² + b³

Steps in finding the special product of (a + b)³ :
a) Cube the first term, a               =  
b) Three (first term)² (last term)   = 3 (a)² (b)   = 3a²b
c) Three (first term) (last term)²   = 3 (a) (b)²   = 3ab²
d)  Cube the last term                  =

Combine the results, the special product is:
a³ + 3a²b + 3ab³ + b³
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