Answers

2014-07-07T17:50:16+08:00
2 x^{2} +4x-3=0
a=2;b=4;c=-3
x= \frac{-b+or- \sqrt{b^2-4ac} }{2a}
x= \frac{-(4) +or- \sqrt{(4)^2-4(2)(-3)} }{2(2)}
x= \frac{-4 +or- \sqrt{16+24} }{4}
x= \frac{-4 +or- \sqrt{40} }{4}
x=-1 +or-\sqrt{40} (Nakuha po yung -1√40 kasi po sinimplify po yung -4 and 4)
2 4 2
:)
Ok na po :)
gets ko na poh .. thank u poh :)
You're welcome po ^_^
yung sa pinaka ans . poh .. dbah poh dpat my square root poh ung 40 .. kc poh positive sia hnd negative ??