Answers

2016-01-31T11:14:03+08:00
T1 = initial temperature
P1 = initial pressure
T2 = final temperature
P2 = final pressure

in Gay- lusaac's law equation, where P1T2 = P2T1.

the amount of initial pressure and final temperature is equal to final pressure and initial temperature

in your following question:

P2(final pressure ) = 20°
T1 ( initial temperature)(given K) 273.15 + 20°
P1 ( initial pressure) = 2.50 atm.
T2 ( final temperature ) = ?

find the final temperature by deriving the equation:
since, P1T2 = P2T1
so,
T2 = P2T1 / P1

formula for finding the final temperature:

substitute the given numbers:

T2 = P2T1 / P1
= (760. mmHg)(20°C + 273.15) / (2.50 atm.)
= (760 mmHg / 1 atm.)
= 117 K

therefore, the final temperature is 117 K.
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