Researchers have found that bone structure rather than weight is the best indicator of actual body fat. An estimate of the percent of body fat for a man is given by the polynomial : 0.49x +0.45y-6.36z+8.7

Where x=waist conference in cm
y=skinfold above the pictoral muscle in mm
z=wrist diameter in cm

Estimate the percent of the body fat for a man with these measurements:
1. x=93.7 cm; y=62mm; z=7.3cm
2. x=86.4 cm; y=4.9mm; z=6.2cm
3. x=100.2cm; y=5.7mm; z=8.2cm
4. x=105.3cm; y=6.2mm; z=7.5cm
5. x=90.8cm; y=4.2mm; z= 9.1cm

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Answers

2016-02-09T01:33:43+08:00

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Given:
0.49x + 0.45y - 6.36z + 8.7

x is in cm ; z is in cm; y is in mm. We need to convert y into cm.
1 cm = 10 mm
1) y = 62 mm x 1cm/10mm = 6.20 cm
2) y = 4.9mm x 1cm/10mm = 0.49 cm
3) y = 5.7mm x 1cm/10mm = 0.57 cm
4) y = 6.2mm x 1cm/10mm = 0.62 cm
5) y = 4.2mm x 1cm/10mm = 0.42 cm 

1) 0.49(93.7cm) + 0.45(6.2cm) - 6.36(7.3cm) + 8.7 = 10.98
2) 0.49(86.4cm) + 0.45(0.49cm) - 6.36(6.2cm) + 8.7 =  11.82
3) 0.49(100.2cm) + 0.45(0.57cm) - 6.36(8.2cm) + 8.7 = 5.90
4) 0.49(105.3cm) + 0.45(0.62cm) - 6.36(7.5cm) + 8.7 = 12.88
5) 0.49(90.8cm) + 0.45(0.42cm) - 6.36(9.1cm) + 8.7 = -4.50
 
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