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2016-01-27T22:30:45+08:00

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Point (-3, 4) is located in Quadrant II.
The x value is -3, and y-value is 4.
We need to form a right triangle by connecting a line from a point given to the x-axis, and to the y-axis.
The two sides are -3 and 4 which we label as a and b consecutively.
We have to find the value of hypotenuse by using the formula c= \sqrt{ a^{2}+ b^{2}  } .
Let's solve for c now by substituting -3 and 4 to a and b.
c= \sqrt{ (-3)^{2}+ 4^{2}  }
c= \sqrt{9+16}
c= \sqrt{25}
c=5


Now, we can find now the values of the six trigonometric functions.
sin α = 4/5
cos α = -3/5
tan α = -4/3
cot α = -3/4
sec α = -5/3
csc α = 5/4


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