# Oxygen gas inside a 1.5L gas tank has a pressure of 0.95 atm provide that the temperature remains constant how much pressure is needed to reduce its volume

by 1/2

2
by roselynblacer 04.02.2016

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by 1/2

2
by roselynblacer 04.02.2016

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Boyle's Law states that pressure (gas) is inversely proportional to its volume provided temperature is constant.

This means that if the pressure on a gas decreases its volume will increase.

In this question, the volume should be decreased to half, thus we should expect a higher pressure (may idea ka na na ang dapat mong makuhang sagot ay mas mataas sa original value ng pressure)

Boyle's law formula:

P/V=k (original na formula yan)

P1V1= P2V2 (ito yung formula pag may kailangang baguhin sa mga kung ano sa pressure or volume){note: ung mga numbers 1 at 2 dapat maliit lang sila at nakalagay sa ibabang part ng letters P at V}

P1V1 refers to the original quantity of volume and pressure.

P2V2 refers to the second quantity of vol and pressure

given: P1= 0.95 atm

V1 = 1.5L

V2= .75L (sabi s problem half daw ng orig n volume)

P2 = ?

use P1V1=P2V2

substitute:

.95atm (1.5L)= P2 (.75L)

divide both sides with .75L para maiwan na lang si P2

(.95atm*1.5L)/.75L = P2 solve

1.425 atm*L/.75L=P2

1.92atm=P2

It needs 1.9 atm to decrease the gas' volume to half.

This means that if the pressure on a gas decreases its volume will increase.

In this question, the volume should be decreased to half, thus we should expect a higher pressure (may idea ka na na ang dapat mong makuhang sagot ay mas mataas sa original value ng pressure)

Boyle's law formula:

P/V=k (original na formula yan)

P1V1= P2V2 (ito yung formula pag may kailangang baguhin sa mga kung ano sa pressure or volume){note: ung mga numbers 1 at 2 dapat maliit lang sila at nakalagay sa ibabang part ng letters P at V}

P1V1 refers to the original quantity of volume and pressure.

P2V2 refers to the second quantity of vol and pressure

given: P1= 0.95 atm

V1 = 1.5L

V2= .75L (sabi s problem half daw ng orig n volume)

P2 = ?

use P1V1=P2V2

substitute:

.95atm (1.5L)= P2 (.75L)

divide both sides with .75L para maiwan na lang si P2

(.95atm*1.5L)/.75L = P2 solve

1.425 atm*L/.75L=P2

1.92atm=P2

It needs 1.9 atm to decrease the gas' volume to half.

first, let use the Boyle's law equation V1P1 = V2P2, where ,

V1 = the initial volume

P1 = the intial pressure

V2 = the final volume

P2 = the final pressure

they must be inversely proportional at constant temperature.

Given:

V1 = 1.5 L

P1 = 0.95 atm

V2 = 0.75 L ( change 1/2 to decimal)

V2 = ?

since the unknown is the P2 which is the final pressure then, use this formula of finding final pressure:

P2 = V1P1 / V2

= (1.5 L)(0.95 atm) / (0.75 L)

= 1.9 atm

therefore , the final pressure is needed to reduce it's volume 1/2 is 1.9 atm