# A shopkeeper had 410 sweets. He put some on them into 15 packets containing 12 sweets each. He then put the rest into 24 packets, each containing the same number of sweets. A. How many sweets would there be in each of the 14 packets? B. How many sweets were left?

2
by peachie2k8
In question A, I'm sure it's a typo error, should be 24 and not 14.

## Answers

2016-02-11T16:27:44+08:00
A. In 14 packs there will be 12 sweets per pack. The total is 14(packs) x 12(sweets) = 168 sweets total

B. 15(packs) x 12(sweets) = 180 sweets total
24(packs) x 12(sweets) = 288 sweets total

180 + 288 = 468 sweets total (its too much because "he then put the REST"
so 24(packs) x 12 (sweets) = 288 + 180 = 468 (make it 410) so - 58 = 410

We lack 58 sweets so THERE IS NOTHING LEFT o_o
Sweets are not lacking, packets are.  There are more sweets than available packets. :-)
ikaw na
• Brainly User
2016-02-11T17:52:08+08:00
Step 1:
410 - (12 × 15)
= 410 - 180
= 230  total sweets left after packing 12 sweets each in 15 packets

Step 2:
230 ÷ 24
=   9  sweets for each of 24 packets,  with 16 sweets (remainder) left without packet

Answer:

A:  There would be 9 sweets for each of the 24 packets.

B.  There are 14 sweets left unpacked or without packets.