Answers

2016-02-25T19:46:25+08:00
An odd integer is added to three times the next consecutive odd integer and the sum is 66. Find the two odd integer.
x = first odd integer
x + 2 = second odd integer

x + 3(x + 2) = 66
x + 3x + 6 = 66
4x = 66 - 6
 \frac{4x}{4} = \frac{60}{4}
x = 15 - first odd integer
x + 2 = 17 - second odd integer

Please, kindly correct me if I'm wrong^-^
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