# The area of a rectangle is 560 square inches the length is 3 more than twice the width find the length and the width

1
by Roli1234

• Brainly User
2016-03-07T08:39:09+08:00

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Dimension:
Width: x
Length: 2x + 3
Area: 560 sq. inches

Area = Length x Width

Equation:
(2x + 3) (x) = 560

2x² + 3x = 560

Transform to quadratic equation, ax² + bx + c = 0:
2x² + 3x - 560 = 0

Use Quadratic formula to solve for x:
a = 2     b = 3      c = -560

x₁,₂ =

x₁,₂ =

x₁,₂ =

x₁ =

x₁ = 64/4

x₁ = 16

-------------------

x₂ =

x₂ = -70/4    or   -35/2

Choose the positive root, x₁ = 16

Substitute 16 for x in dimension:
Width:x = 16 inches
Length: 2x + 3 = 2(16) + 3 = 35 inches

ANSWER:  Length is 35 inches and width is 16 inches.

Check:
(35 inches) (16 inches) = 560 sq. inches
560 sq. inches = 560 sq. inches  (true)