# Chris is thrice as old as Diego 8 years from now. Find their present ages if Chris is four times as old as Diego.

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by imee3r

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by imee3r

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Present ages:

Diego: x

Chris: 4x

Ages 8 years from now:

Diego: x + 8

Chris: 4x + 8

Equation:

4x + 8 = 3 (x + 8)

4x + 8 = 3x + 24

4x - 3x = 24 - 8

x = 16

Present ages: (substitute 16 for x)

Diego: 16 years old

Chris: 4 (16) = 64

**ANSWER: Diego is 16 years old and Chris is 64 years old.**

Ages in 8 years:

64 + 8 = 3 (16 + 8)

72 = 3 (24)

72 = 72 (true)

Diego: x

Chris: 4x

Ages 8 years from now:

Diego: x + 8

Chris: 4x + 8

Equation:

4x + 8 = 3 (x + 8)

4x + 8 = 3x + 24

4x - 3x = 24 - 8

x = 16

Present ages: (substitute 16 for x)

Diego: 16 years old

Chris: 4 (16) = 64

Ages in 8 years:

64 + 8 = 3 (16 + 8)

72 = 3 (24)

72 = 72 (true)