# The pressure of a nitrogen gas inside a rigid tank is 1.5 atmosphere at 30 degrees Celsius. What would be the resulting pressure if the tank is cooled to 0 degree Celsius?

1
Log in to add a comment

Log in to add a comment

You can solve it using Gay Lussac's Law. P1/T1 = P2/T2

1.5 atm / 303.15 K = P2 / 273.15 K

P2(303.15 K) = 1.5 atm (273.15 K)

P2 = 1.5 atm (273.15 K) / 303.15 K

P2 = 1.5 atm (273.15) / 303.15

P2 = 409.73 atm / 303.15

P2 = 1.35 atm