Answers

2016-04-01T22:30:13+08:00
If repetitions are not allowed,  and order does not matter
  then this is a combination without repetitions problem
    using the formula         n!/r!(n-r)!       /    n = 52  and   r = 5
            we have      52!/5!(52-5)!
                            =   52!/5!(47!)
                             =  52*51*50*49*48/5*4*3*2*1
                             = 311,875,200/120   
                             =  2,598,960  sets of 5 cards each
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