Answers

2016-04-20T00:51:34+08:00
Let x =  first odd integers
     x+2 =  second odd integers
     x+ 4 + = third odd integers
     x + 6   = fourth odd integers
thus     x +(x+2)+ (x+4)+( x+ 6)  =   152
            4 x + 12 =152
              x =  (152-12)/4
                 =  35
    therefore  the 4 odd integers are
        35 + 37+ 39 + 41  =   152
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2016-04-20T03:10:43+08:00
Let the four consecutive odd integers be x, x+2, x+4 and x+6.

Their sum is 152.

∴ x + x + 2 + x + 4 + x + 6 = 152
∴4x + 12 = 152
∴4x = 152 - 12
∴4x = 140
∴x = 140/4
∴x = 35

Thus, the four consecutive odd integers are 35, 37, 39 and 41.
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