Answers

2014-07-10T19:47:45+08:00
2014-07-10T19:50:07+08:00
64y^3 - 16y^2 + y

= y(64y^2 - 16y + 1)
= y [16y(4y - 1) +1]
0
You do realize that you just have rewritten the equation.
I factored it out.
Actually 64y^2-16y+1 is a perfect square trinomial.
It is equal to (8y-1)^2