Answers

2016-06-03T11:02:31+08:00
There are 15 possibble different ways they can be seated.
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  • Brainly User
2016-06-03T11:56:52+08:00
Combination (order of arrangement or ways to be seated does not natter):

C(n, r)   where: n = 7;  r=3
  
C(7,3) = 7! / 3! (7-3)!

C(7,3) = 7! / 3!(4!)

C (7,3) =  \frac{7x6x5x4x3x2x1}{3x2x1 (4x3x2x1)}     

C(7,3) =  \frac{7x6x5}{3x2x1}

C(7,3) = 210/6

C(7,3) = 35

ANSWER:  There are 35 possible ways the three additional passengers can be seated in 7 vacant seats.

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