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The length of a box is 5 meters less than twice the width. the height is 4 meters more than 3 times the width. the box has a volume of 520 cubic meters.

which of the following equations can be used to find the height of the box??

A. W(2L-5)(3H+4)=520
B. W(2W+5)(3W-4)=520
C. W(2W-5)(3W-4)=520


     Width:  W
     Length:  2W - 5  (5 meters less than twice the width)
     Height:  3W + 4  (4 meters more than 3 times the width)

Volume of rectangular box:
    (w) (L) (H) = 520

    (W) (2W-5) (3x + 4) = 520

1 5 1
Typo error, should be: (W)(2W-5)(3W + 4) = 520, and not (3x + 4).
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