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In this case, we can just list the numbers formed by rearranging the digits 0, 1 and 2. It would be: 012, 021, 102, 120, 201, 210. In this list, 012 and 021 would be disregarded because 0 in the hundreds' place has no value and it would technically become a 2-digit number. Among the numbers left, there are 3 (102, 120 and 210) even numbers. So the answer is 3.