Answers

2014-07-12T15:53:09+08:00
(x²ⁿ+2xⁿyⁿ+y²ⁿ)(x²ⁿ-2xⁿyⁿ+y²ⁿ)

If you look closely, you'll notice that it can also be expressed in the form of:

[(xⁿ)²+2(xⁿ)(yⁿ)+(yⁿ)²]](xⁿ)²-2(xⁿ)(yⁿ)+(yⁿ)²]
=[(xⁿ + yⁿ)²][(xⁿ - yⁿ)²]
=(xⁿ + yⁿ)(xⁿ + yⁿ)(xⁿ - yⁿ)(xⁿ - yⁿ)
=[(xⁿ + yⁿ)(xⁿ - yⁿ)][(xⁿ + yⁿ)(xⁿ - yⁿ)]
=(x²ⁿ - y²ⁿ)(x²ⁿ - y²ⁿ)
=(x²ⁿ - y²ⁿ)²
 x^{4n} -2 x^{2n} y^{2n}  + y^{4n}

but of course, if you prefer manual multiplication... well, no one's stopping you
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