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transpose 4 to the other side of equation

x²-6x= -4

make the equation a perfect square trinomial

divide -6 by 2, and square the product

(-3)² = 9

x²-6x+9= -4+9

x²-6x+9= 5

find the factors of the equation

(x-3)² = 5

find the square root of the both side

√(x-3)² = √5

x-3 = √5 or -√5

transpose -3

x= 3 √5 or x= 3 -√5

^_____^