Answers

2016-06-18T16:43:59+08:00
( x-4)^{2}= x^{2} -8x+16
Therefore,
 x^{2} -8x+16+8=0 is equal to
 x^{2} -8x+24=0.
So the standard form is 
 x^{2} -8x+24=0
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