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To know the product of (4x-3)(4x+3),
First multiply 4x by 4x, which will results in 16 x^{2} ,
Then multiply 4x by -3 and is equal to -12x.
Then multiply 4x by 3, that is equal to 12x.
Then multiply the last term, +3 times -3 and is equal to -9.
Lastly arranged: ( 16x^{2} -12x+12x-9=0. You can cancel -12x and 12x since when you add them it will give you 0.

So, the product of (4x-3)(4x+3)=16 x^{2} -9.
0 0 0
(4x)^{2} -3^{2}
4^{2} x^{2} -3^{2}
16x^{2} -3^{2}
Answer: 16x^{2} -9
0 0 0
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