Answers

2016-06-21T21:15:08+08:00
Standard form
f(x) = ax^2 + bx + c

a = 1; b = 1; c = 16
x^2 - x + 16 = 0

0
2016-06-21T21:18:10+08:00
■ (x-4)(x-4) ■ x² -8 +16 =0 a=1 b=16 c=16
1 3 1
oh thnks for the correction
it should be x^2 - 8 +16 so a=1 b=-8 and c= 16
thanks , but it should have equals 0
okay it should be x²-8+16=0
thanks :)