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G(x) =  \frac{1}{x-1}

The denominator can not be zero so that the expression will not be rendered undefined.

Therefore, x can be any value except 1  because if x is 1, then:
      \frac{1}{x-1} = \frac{1}{1-1}= \frac{1}{0}

The domain (x) = {x/x an ∈ of real number,  ≠ 1}
Range (y) = {y / y ≠ 0}
0 0 0
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