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## Answers

a₂ = 4

a₃ = 10

a₄ = 16

a₅ = ?

So, we're looking for a₁ and a₅.

Find the difference between any two consecutive term:

10 - 4 =

**6**

16 - 10 =

**6**

**d**(common difference) =

**6**

**From the general formula/rule:**

an= a₁ + (n-1) (d)

Rule of the sequence:

Say we choose a₄ = 16 as our an, and its term is n = 4, d = 6

Then:

16 = a₁ + (4-1) (6)

16 = a₁ = (3) (6)

16 = a₁ + 18

16 - 18 = a₁

**a₁ = -2**

To find a₅:

a₅ = a₁ + (5-1)(6)

a₅ = -2 + (4) (6)

a₅ = -2 + 24

**a₅ = 22**

Follow this rule to find the other terms, when needed.

**The missing terms are:**

**a₁ = -2**

**a₅ = 22**

**-2**, 4, 10, 16,

**22**