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## Answers

Standard form:

2r² - 32 = 0

a = 2 b = 0 c = -32

1) First, let's determine the nature of its roots, by finding the discriminant (k):

k = b² - 4(a)(c)

k = (0)² - 4(2) (-32)

k = 256 and 256 > 0 (that, is k > 0)

If k > 0 and is a perfect square (256 is a perfect square), then the equation

**has two rational solutions.**

2) Find the roots.

Method - Extracting the roots (Use this method when b = 0).

2r² = 32

2r²/2 = 32/2

r² = 16

**r = +4 and - 4 (two roots)**