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First, we need to find all numbers that satisfy the condition. Represent each 2-digit number by 10x+y (x is the tens digit, y is the units digit)

Condition: the number is divisible by each of its digits.

Divisible by x:

is a positive integer because it is the quotient. This implies that is a positive integer as well. (a)

Let (b)

Divisible by y:

is also a positive integer because it is the quotient.

But , So p should be a positive integer [from (a)] such that is a positive integer.

The only possible values for p are 1, 2, and 5. Recall that p is the ratio between the ones and the tens digit [from (b)].

List of numbers when p=1 {11, 22, 33, 44, 55, 66, 77, 88, 99} p=2 {12, 24, 36, 48} p=5 {15}

These are all the 2-digit positive integers that satisfy the condition.

Take time to read. Sa unang basa, nakakahilo talaga, so read again kung di gets :) Don't hesitate to ask kung may part ka na di talaga maintindihan.

okay po, i find it hard to represent....nahihilo po ako kung ano ang gagamitin ko po as tens and ones :(

Kahit anong letter pwede mong gamitin. Ang mahalaga lang ay yung 10 sa tens digit. For example, ang two digit number ko ay 48. So, gamit yung representation sa taas, x=4 and y=8. Kung wala yung 10 sa 10x+y, magiging x+y lang sya, which is equal to 12 and not 48.

Isipin mo na bawat digit ay may katumbas na value. Sa 48 ang value ng 4 ay 40, kaya kailangan imultiply sa 10. Ganon din ang gagawin sa ibang digits in different place values. For example, to represent a 3-digit integer, I will use 100a + 10b + c

ahhhhh okay po, gets ko na yung pag represent..thank you po!!!!